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Word Problems

Example 1

The area of a rectangle is 65 cm^2. The length is 2 less than three times the width. Find the length and the width.

 

To solve:

 

First, you need to find binomials that represent the dimensions of the rectangles.

->Let w represent the width

->Let (3w-2) represent the length

 

Now, solve.

 

A= wl

A= w (3w-2)                            ->Expand and simplify  

A= 3w^2 - 2w

65 = 3w^2 - 2w                       ->We know that A=65

0 = 3w^2 -  2w - 65                 ->Make one side = 0

0 = 3w^2 - 15w + 13w -65      ->Factor the complex trinomial

0 = (3w^2 - 15w) + (13w-65)  ->Factor by grouping

0 = 3w (w-5) + 13 (w-5)

0 = (w-5)(3w+13)

 

w-5      3w+13

w=5     w=-4.33

 

The width is 5cm. It cannot be -4.33 because the rectangle cannot have negative dimensions.

 

If w=5. Find the length

3(5)-2 = 13

 

Therefore the dimensions are 5x13.

 

Example 2
 

The height of the ball thrown can be approximated by the formula h= -3t^2 + 12t + 36, where t is the time, in seconds, and h is the height, in metres.

 

a) When does the ball land on the ground?

b) What is the maximum height the ball reaches, and when does it reach its maximum height? *My video*

Example 3
 

1. a)Write and simplfy an expression for the area of the area of the shaded region.

    b) If x=7, find the area of the shaded region. *My video*

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